Lesson 08 / 12 · Common upstream assets
Find a single point of failure
What happens to two paths when their common main bus fails?
Predict before you run
Write down your prediction, then change only the input below. In the interactive lesson, compare the starting case with the challenge and export a worksheet to retain your reasoning.
| Input | Starting value | Challenge value |
|---|---|---|
| Main bus available (0 = failed, 1 = available) | 0 | 1 |
Reported quantity: kWh unserved. The live control accepts 0–1.
Worked answer
The common bus outage lasts 600 s. Even with two downstream paths, 1,000 × 600/3,600 = 166.666… kWh is unserved. Keeping the bus available removes the interruption.
Reproduce the configuration
| IT demand / simulated duration | 1000 kW / 1800 s |
|---|---|
| Opening battery / energy capacity | 100 kWh / 100 kWh |
| Charging power limit | 100 kW |
| Charge / discharge efficiency | 0.95 / 0.9 |
| Distribution efficiency | 0.95 |
| Generator start delay | 30 s |
Scheduled events
- 300 s: main-bus — asset down
- 900 s: main-bus — asset up
The browser lesson applies its configuration to the normal preset. Open it above, run the starting case, switch to the challenge, and use “Verify against Python” to compare complete results. Use the worksheet export to keep the prediction, completed inputs and answer together.
Sources and verification
- Exact lesson definitions and input transformations
- Native Python default/challenge checks
- 1 MW equations and independent energy-ledger reconstruction
- Electrical continuity contract
Original material by Mohammad Rezwan Khan, engine 1.0.0. Synthetic teaching cases; no facility calibration or independent external reproduction has been established. Annual PUE planning and outage continuity are different calculations. Full scope and evidence.