Lesson 01 / 12 · kW and kWh
Power becomes energy
How much energy does a constant load request in half an hour?
Predict before you run
Write down your prediction, then change only the input below. In the interactive lesson, compare the starting case with the challenge and export a worksheet to retain your reasoning.
| Input | Starting value | Challenge value |
|---|---|---|
| IT demand | 1000 kW | 500 kW |
Reported quantity: kWh. The live control accepts 0–1000 kW.
Worked answer
Energy equals power multiplied by time. At 1,000 kW for 0.5 h the request is 500 kWh; at 500 kW it is 250 kWh.
Reproduce the configuration
| IT demand / simulated duration | 1000 kW / 1800 s |
|---|---|
| Opening battery / energy capacity | 100 kWh / 100 kWh |
| Charging power limit | 100 kW |
| Charge / discharge efficiency | 0.95 / 0.9 |
| Distribution efficiency | 0.95 |
| Generator start delay | 30 s |
Scheduled events
No failure or recovery events are scheduled.
The browser lesson applies its configuration to the normal preset. Open it above, run the starting case, switch to the challenge, and use “Verify against Python” to compare complete results. Use the worksheet export to keep the prediction, completed inputs and answer together.
Sources and verification
- Exact lesson definitions and input transformations
- Native Python default/challenge checks
- 1 MW equations and independent energy-ledger reconstruction
- Electrical continuity contract
Original material by Mohammad Rezwan Khan, engine 1.0.0. Synthetic teaching cases; no facility calibration or independent external reproduction has been established. Annual PUE planning and outage continuity are different calculations. Full scope and evidence.